A 25 ft long ladder is placed against the wall with its base 7 ft from the wall. The base of the ladder is dra

Question

A 25 ft long ladder is placed against the wall with its base 7 ft from the wall. The base of the ladder is drawn out so that the top comes down by half the distance that the base is drawn out. This distance is in the range:

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Accepted Answer

None of the above.. Original position of the ladder = AC = 25 25 25 ft Base = BC = 7 7 7 ft => In △ 	riangle △ ABC, using Pythagoras theorem => ( A B ) 2 = ( A C ) 2 − ( B C ) 2 (AB)^2 = (AC)^2 - (BC)^2 ( A B ) 2 = ( A C ) 2 − ( B C ) 2 => ( A B ) 2 = ( 25 ) 2 − ( 7 ) 2 (AB)^2 = (25)^2 - (7)^2 ( A B ) 2 = ( 2