A ball of diameter 4 cm is kept on top of a hollow cylinder standing vertically. The height of the cylinder is

Question

A ball of diameter 4 cm is kept on top of a hollow cylinder standing vertically. The height of the cylinder is 3 cm, while its volume is $$9\pi$$ cubic centimeters. Then the vertical distance, in cm, of the topmost point of the ball from the base of the cylinder is

Accepted Answer

The volume of a cylinder is π ∗ r 2 ∗ 3 = 9 π \pi * r^2 * 3 = 9 \pi π ∗ r 2 ∗ 3 = 9 π r = 3 \sqrt{3} 3 ​ cm. Radius of the ball is 2 cm. Hence, the ball will lie on top of the cylinder. Lets draw the figure. Based on the Pythagoras theorem, the other leg will be 1 cm. Thus, the height will be 3 + 1

A ball of diameter 4 cm is kept on top of a hollow cylinder standing vertically. The height of the cylinder is 3 cm, while its volume is 9π9\pi9π cubic centimeters. Then the vertical distance, in cm, of the topmost point of the ball from the base of the cylinder is

A ball of diameter 4 cm is kept on top of a hollow cylinder standing vertically. The height of the cylinder is 3 cm, while its volume is $9\pi$ cubic centimeters. Then the vertical distance, in cm, of the topmost point of the ball from the base of the cylinder is