A man makes complete use of 405 cc of iron, 783 cc of aluminium, and 351 cc of copper to make a number of soli

Question

A man makes complete use of 405 cc of iron, 783 cc of aluminium, and 351 cc of copper to make a number of solid right circular cylinders of each type of metal. These cylinders have the same volume and each of these has radius 3 cm. If the total number of cylinders is to be kept at a minimum, then the total surface area of all these cylinders, in sq cm, is

Select an option to reveal the answer and explanation

Accepted Answer

1026 ( 1 + π ) 1026(1 + \pi) 1026 ( 1 + π ). It is given that the volume of all the cylinders is the same, so the volume of each cylinder = HCF of (405, 783, 351) =27 The number of iron cylinders = 405 27 \ \frac{\ 405}{27} 27 405 ​ = 15 The number of aluminium cylinders = 783 27 \ \frac{\ 783}{27} 27 783 ​ = 29 The number of copper cylinders