A motorbike leaves point A at 1 pm and moves towards point B at a uniform speed. A car leaves point B at 2 pm

Question

A motorbike leaves point A at 1 pm and moves towards point B at a uniform speed. A car leaves point B at 2 pm and moves towards point A at a uniform speed which is double that of the motorbike. They meet at 3:40 pm at a point which is 168 km away from A. What is the distance, in km, between A and B7

Select an option to reveal the answer and explanation

Accepted Answer

378. Let the distance traveled by the car be x KMs Distance traveled by the bike = 168 KMs Speed of car is double the speed of bike => x 3 : 40 − 2 : 00 \frac{x}{3:40 - 2:00} 3 : 40 − 2 : 00 x ​ = 2 × 168 3 : 40 − 1 : 00 2 	imes \frac{168}{3:40 - 1:00} 2 × 3 : 40 − 1 : 00 168 ​ => x 100 \frac{x}{1