Consider the sequence t1=1,t2=−1t_1 = 1, t_2 = -1t1=1,t2=−1 and tn=(n−3n−1)tn−2t_n = \left(\cfrac{n - 3}{n - 1}\right)t_{n - 2}tn=(n−1n−3)tn−2 for n≥3n \geq 3n≥3. Then, the value of the sum 1t2+1t4+1t6+.......+1t2022+1t2024\cfrac{1}{t_2} + \cfrac{1}{t_4} + \cfrac{1}{t_6} + ....... +\cfrac{1}{t_{2022}} + \cfrac{1}{t_{2024}}t21+t41+t61+.......+t20221+t20241, is
-1024144
-1022121
-1023132
-1026169
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