$$f(x) = \frac{x^2 + 2x - 15}{x^2 - 7x - 18}$$ is negative if and only if

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-5 < x < -2 or 3 < x < 9. f ( x ) = x 2 + 2 x − 15 x 2 − 7 x − 18 f(x) = \frac{x^2 + 2x - 15}{x^2 - 7x - 18} f ( x ) = x 2 − 7 x − 18 x 2 + 2 x − 15 ​ <0 \frac{\left(x+5\right)\left(x-3\right)}{\left(x-9\right)\left(x+2\right)}&lt;0 We have four inflection points -5, -2, 3, and 9. For x<-5, all four terms (x+5), (x

$f(x) = \frac{x^2 + 2x - 15}{x^2 - 7x - 18}$ is negative if and only if

$f(x) = \frac{x^2 + 2x - 15}{x^2 - 7x - 18}$ is negative if and only if

f(x)=x2+2x−15x2−7x−18f(x) = \frac{x^2 + 2x - 15}{x^2 - 7x - 18}f(x)=x2−7x−18x2+2x−15​ is negative if and only if

f(x)=x2+2x−15x2−7x−18f(x) = \frac{x^2 + 2x - 15}{x^2 - 7x - 18}f(x)=x2−7x−18x2+2x−15​ is negative if and only if

$f(x) = \frac{x^2 + 2x - 15}{x^2 - 7x - 18}$ is negative if and only if

$f(x) = \frac{x^2 + 2x - 15}{x^2 - 7x - 18}$ is negative if and only if