Given that $$x^{2018}y^{2017}=\frac{1}{2}$$, and $$x^{2016}y^{2019}=8$$, then value of $$x^{2}+y^{3}$$ is

Question

Accepted Answer

33 4 \dfrac{33}{4} 4 33 ​. Given that x 2018 y 2017 = 1 2 x^{2018}y^{2017}=\frac{1}{2} x 2018 y 2017 = 2 1 ​ ... (1) x 2016 y 2019 = 8 x^{2016}y^{2019}=8 x 2016 y 2019 = 8 ... (2) Equation (2)/ Equation (1) y 2 x 2 = 8 1 / 2 \dfrac{y^2}{x^2} = \dfrac{8}{1/2} x 2 y 2 ​ = 1/2 8 ​ y x = 4 \dfrac{y}{x} = 4 x y ​ = 4 or − 4 -4 − 4

Given that $x^{2018}y^{2017}=\frac{1}{2}$ , and $x^{2016}y^{2019}=8$ , then value of $x^{2}+y^{3}$ is

Given that $x^{2018}y^{2017}=\frac{1}{2}$ , and $x^{2016}y^{2019}=8$ , then value of $x^{2}+y^{3}$ is

Given that x2018y2017=12x^{2018}y^{2017}=\frac{1}{2}x2018y2017=21​, and x2016y2019=8x^{2016}y^{2019}=8x2016y2019=8, then value of x2+y3x^{2}+y^{3}x2+y3 is

Given that x2018y2017=12x^{2018}y^{2017}=\frac{1}{2}x2018y2017=21​, and x2016y2019=8x^{2016}y^{2019}=8x2016y2019=8, then value of x2+y3x^{2}+y^{3}x2+y3 is

Given that $x^{2018}y^{2017}=\frac{1}{2}$ , and $x^{2016}y^{2019}=8$ , then value of $x^{2}+y^{3}$ is

Given that $x^{2018}y^{2017}=\frac{1}{2}$ , and $x^{2016}y^{2019}=8$ , then value of $x^{2}+y^{3}$ is