If $$3x+2\mid y\mid+y=7$$ and $$x+\mid x \mid+3y=1$$ then $$x+2y$$ is:

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0 0 0. We need to check for all regions: x >= 0, y >= 0 x >= 0, y < 0 x < 0, y >= 0 x < 0, y < 0 However, once we find out the answer for any one of the regions, we do not need to calculate for other regions since the options suggest that there will be a single answer. Let us start

If $3x+2\mid y\mid+y=7$ and $x+\mid x \mid+3y=1$ then $x+2y$ is:

If $3x+2\mid y\mid+y=7$ and $x+\mid x \mid+3y=1$ then $x+2y$ is:

If 3x+2∣y∣+y=73x+2\mid y\mid+y=73x+2∣y∣+y=7 and x+∣x∣+3y=1x+\mid x \mid+3y=1x+∣x∣+3y=1 then x+2yx+2yx+2y is:

If 3x+2∣y∣+y=73x+2\mid y\mid+y=73x+2∣y∣+y=7 and x+∣x∣+3y=1x+\mid x \mid+3y=1x+∣x∣+3y=1 then x+2yx+2yx+2y is:

If $3x+2\mid y\mid+y=7$ and $x+\mid x \mid+3y=1$ then $x+2y$ is:

If $3x+2\mid y\mid+y=7$ and $x+\mid x \mid+3y=1$ then $x+2y$ is: