If $$5 - \log_{10}\sqrt{1 + x} + 4 \log_{10} \sqrt{1 - x} = \log_{10} \frac{1}{\sqrt{1 - x^2}}$$, then 100x eq

Question

If $$5 - \log_{10}\sqrt{1 + x} + 4 \log_{10} \sqrt{1 - x} = \log_{10} \frac{1}{\sqrt{1 - x^2}}$$, then 100x equals

Accepted Answer

5 − log ⁡ 10 1 + x + 4 log ⁡ 10 1 − x = log ⁡ 10 1 1 − x 2 5 - \log_{10}\sqrt{1 + x} + 4 \log_{10} \sqrt{1 - x} = \log_{10} \frac{1}{\sqrt{1 - x^2}} 5 − lo g 10 ​ 1 + x ​ + 4 lo g 10 ​ 1 − x ​ = lo g 10 ​ 1 − x 2 ​ 1 ​ We can re-write the equation as: 5 − log ⁡ 10 1 + x + 4 log ⁡ 10 1 − x = log ⁡ 10

If $5 - \log_{10}\sqrt{1 + x} + 4 \log_{10} \sqrt{1 - x} = \log_{10} \frac{1}{\sqrt{1 - x^2}}$ , then 100x equals

If $5 - \log_{10}\sqrt{1 + x} + 4 \log_{10} \sqrt{1 - x} = \log_{10} \frac{1}{\sqrt{1 - x^2}}$ , then 100x equals

If 5−log⁡101+x+4log⁡101−x=log⁡1011−x25 - \log_{10}\sqrt{1 + x} + 4 \log_{10} \sqrt{1 - x} = \log_{10} \frac{1}{\sqrt{1 - x^2}}5−log10​1+x​+4log10​1−x​=log10​1−x2​1​, then 100x equals

If 5−log⁡101+x+4log⁡101−x=log⁡1011−x25 - \log_{10}\sqrt{1 + x} + 4 \log_{10} \sqrt{1 - x} = \log_{10} \frac{1}{\sqrt{1 - x^2}}5−log10​1+x​+4log10​1−x​=log10​1−x2​1​, then 100x equals

If $5 - \log_{10}\sqrt{1 + x} + 4 \log_{10} \sqrt{1 - x} = \log_{10} \frac{1}{\sqrt{1 - x^2}}$ , then 100x equals

If $5 - \log_{10}\sqrt{1 + x} + 4 \log_{10} \sqrt{1 - x} = \log_{10} \frac{1}{\sqrt{1 - x^2}}$ , then 100x equals