If $$a_1 + a_2 + a_3 + .... + a_n = 3(2^{n + 1} - 2)$$, for every $$n \geq 1$$, then $$a_{11}$$ equals

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Accepted Answer

11th term of series = a 11 a_{11} a 11 ​ = Sum of 11 terms - Sum of 10 terms = 3 ( 2 11 + 1 − 2 ) 3(2^{11 + 1} - 2) 3 ( 2 11 + 1 − 2 ) -3 ( 2 10 + 1 − 2 ) (2^{10 + 1} - 2) ( 2 10 + 1 − 2 ) = 3 ( 2 12 − 2 − 2 11 + 2 ) (2^{12} - 2-2^{11} +2) ( 2 12 − 2 − 2 11 + 2 ) =3 ( 2 11 ) ( 2 − 1 ) (2^{11})(2-1)

If $a_1 + a_2 + a_3 + .... + a_n = 3(2^{n + 1} - 2)$ , for every $n \geq 1$ , then $a_{11}$ equals

If $a_1 + a_2 + a_3 + .... + a_n = 3(2^{n + 1} - 2)$ , for every $n \geq 1$ , then $a_{11}$ equals

If a1+a2+a3+....+an=3(2n+1−2)a_1 + a_2 + a_3 + .... + a_n = 3(2^{n + 1} - 2)a1​+a2​+a3​+....+an​=3(2n+1−2), for every n≥1n \geq 1n≥1, then a11a_{11}a11​ equals

If a1+a2+a3+....+an=3(2n+1−2)a_1 + a_2 + a_3 + .... + a_n = 3(2^{n + 1} - 2)a1​+a2​+a3​+....+an​=3(2n+1−2), for every n≥1n \geq 1n≥1, then a11a_{11}a11​ equals

If $a_1 + a_2 + a_3 + .... + a_n = 3(2^{n + 1} - 2)$ , for every $n \geq 1$ , then $a_{11}$ equals

If $a_1 + a_2 + a_3 + .... + a_n = 3(2^{n + 1} - 2)$ , for every $n \geq 1$ , then $a_{11}$ equals