If f(x)=(x2+3x)(x2+3x+2)f(x)= (x^{2} + 3x)(x^{2}+ 3x+2)f(x)=(x2+3x)(x2+3x+2) then the sum of all real roots of the equation f(x)+1=9701\sqrt{f(x)+1}= 9701f(x)+1=9701, is
-6
6
3
-3
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