If log1281=p\log_{12}{81}=plog1281=p, then 3(4−p4+p)3(\dfrac{4-p}{4+p})3(4+p4−p) is equal to
log416\log_{4}{16}log416
log616\log_{6}{16}log616
log28\log_{2}{8}log28
log68\log_{6}{8}log68
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