If log4m+log4n=log2(m+n)\log_4m + \log_4n = \log_2(m + n)log4m+log4n=log2(m+n) where m and n are positive real numbers, then which of the following must be true?
1m+1n=1\frac{1}{m} + \frac{1}{n} = 1m1+n1=1
m = n
m2+n2=1m^2 + n^2 = 1m2+n2=1
1m+1n=2\frac{1}{m} + \frac{1}{n} = 2m1+n1=2
No values of m and n can satisfy the given equation
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