If $$m$$ and $$n$$ are natural numbers such that $$n 1$$, and $$m^n = 2^{25} imes 3^{40}$$, then $$m -

Question

If $$m$$ and $$n$$ are natural numbers such that $$n > 1$$, and $$m^n = 2^{25} 	imes 3^{40}$$, then $$m - n$$ equals

Accepted Answer

209947. We must bring the right-hand side in the form so that everything has the same power. 25 has factors 1, 5 and 25 The only common factor 40 and 25 have is 5 (other than 1 of course, which does not work) So the right-hand side can be rewritten as ( 2 5 ) 5 × ( 3 8 ) 5 \left(2^5ight)^5	imes\ \left(3^

If $m$ and $n$ are natural numbers such that $n > 1$ , and $m^n = 2^{25} \times 3^{40}$ , then $m - n$ equals

If $m$ and $n$ are natural numbers such that $n > 1$ , and $m^n = 2^{25} \times 3^{40}$ , then $m - n$ equals

If mmm and nnn are natural numbers such that n &gt; 1, and mn=225×340m^n = 2^{25} \times 3^{40}mn=225×340, then m−nm - nm−n equals

If mmm and nnn are natural numbers such that n &gt; 1, and mn=225×340m^n = 2^{25} \times 3^{40}mn=225×340, then m−nm - nm−n equals

If $m$ and $n$ are natural numbers such that $n > 1$ , and $m^n = 2^{25} \times 3^{40}$ , then $m - n$ equals

If $m$ and $n$ are natural numbers such that $n > 1$ , and $m^n = 2^{25} \times 3^{40}$ , then $m - n$ equals