If $$(x + 6\sqrt{2})^{\cfrac{1}{2}} - (x - 6\sqrt{2})^{\cfrac{1}{2}} = 2\sqrt{2}$$, then x equals

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Accepted Answer

Squaring on both sides, we get: x + 6 2 + x − 6 2 − 2 ( x 2 − 72 ) 1 2 = 8 x+6\sqrt{\ 2}+x-6\sqrt{\ 2}-2\left(x^2-72\right)^{\frac{1}{2}}=8 x + 6 2 ​ + x − 6 2 ​ − 2 ( x 2 − 72 ) 2 1 ​ = 8 x − ( x 2 − 72 ) 1 2 = 4 x-\left(x^2-72\right)^{\frac{1}{2}}=4 x − ( x 2 − 72 ) 2 1 ​ = 4 Bringing x to the oth

If $(x + 6\sqrt{2})^{\cfrac{1}{2}} - (x - 6\sqrt{2})^{\cfrac{1}{2}} = 2\sqrt{2}$ , then x equals

If $(x + 6\sqrt{2})^{\cfrac{1}{2}} - (x - 6\sqrt{2})^{\cfrac{1}{2}} = 2\sqrt{2}$ , then x equals

If (x+62)12−(x−62)12=22(x + 6\sqrt{2})^{\cfrac{1}{2}} - (x - 6\sqrt{2})^{\cfrac{1}{2}} = 2\sqrt{2}(x+62​)21​−(x−62​)21​=22​, then x equals

If (x+62)12−(x−62)12=22(x + 6\sqrt{2})^{\cfrac{1}{2}} - (x - 6\sqrt{2})^{\cfrac{1}{2}} = 2\sqrt{2}(x+62​)21​−(x−62​)21​=22​, then x equals

If $(x + 6\sqrt{2})^{\cfrac{1}{2}} - (x - 6\sqrt{2})^{\cfrac{1}{2}} = 2\sqrt{2}$ , then x equals

If $(x + 6\sqrt{2})^{\cfrac{1}{2}} - (x - 6\sqrt{2})^{\cfrac{1}{2}} = 2\sqrt{2}$ , then x equals