If $$x$$ and $$y$$ are positive real numbers such that $$\log_{x}(x^2 + 12) = 4$$ and $$3 \log_{y} x = 1$$, th

Question

If $$x$$ and $$y$$ are positive real numbers such that $$\log_{x}(x^2 + 12) = 4$$ and $$3 \log_{y} x = 1$$, then $$x + y $$ equals

Accepted Answer

10. Given, log ⁡ x ( x 2 + 12 ) = 4 \log_{x}(x^2 + 12) = 4 lo g x ​ ( x 2 + 12 ) = 4 => x 2 + 12 = x 4 x^2+12=x^4 x 2 + 12 = x 4 => x 4 − x 2 − 12 = 0 x^4-x^2-12=0 x 4 − x 2 − 12 = 0 => x 4 − 4 x 2 + 3 x 2 − 12 = 0 x^4-4x^2+3x^2-12=0 x 4 − 4 x 2 + 3 x 2 − 12 = 0 => x 2 ( x 2 − 4 ) + 3 ( x 2

If $x$ and $y$ are positive real numbers such that $\log_{x}(x^2 + 12) = 4$ and $3 \log_{y} x = 1$ , then $x + y$ equals

If $x$ and $y$ are positive real numbers such that $\log_{x}(x^2 + 12) = 4$ and $3 \log_{y} x = 1$ , then $x + y$ equals

If xxx and yyy are positive real numbers such that log⁡x(x2+12)=4\log_{x}(x^2 + 12) = 4logx​(x2+12)=4 and 3log⁡yx=13 \log_{y} x = 13logy​x=1, then x+yx + yx+y equals

If xxx and yyy are positive real numbers such that log⁡x(x2+12)=4\log_{x}(x^2 + 12) = 4logx​(x2+12)=4 and 3log⁡yx=13 \log_{y} x = 13logy​x=1, then x+yx + yx+y equals

If $x$ and $y$ are positive real numbers such that $\log_{x}(x^2 + 12) = 4$ and $3 \log_{y} x = 1$ , then $x + y$ equals

If $x$ and $y$ are positive real numbers such that $\log_{x}(x^2 + 12) = 4$ and $3 \log_{y} x = 1$ , then $x + y$ equals