In a circle with center C and radius $$6\sqrt{2}$$ cm, PQ and SR are two parallel chords separated by one of t

Question

In a circle with center C and radius $$6\sqrt{2}$$ cm, PQ and SR are two parallel chords separated by one of the diameters. If $$\angle PQC=45^{0}$$, and the ratio of the perpendicular distance of $$PQ$$ and $$SR$$ from $$C$$ is $$3:2$$, then the area, in sq. cm, of the quadrilateral $$PQRS$$ is

Accepted Answer

20 ( 3 + 14 ) 20(3+\sqrt{14}) 20 ( 3 + 14 ​ ). The radius of the circle is given to be 6 2 6\sqrt{2} 6 2 ​ cm. We are also given that the ratio of CA to CB is 3:2. So, if we assume the value of CA to be 3x, then the value of CB becomes 2x. We are also given that ∠ P Q C = 45 0 \angle PQC=45^{0} ∠ P QC = 4 5 0 and since PCQ is an isosceles triang

In a circle with center C and radius $6\sqrt{2}$ cm, PQ and SR are two parallel chords separated by one of the diameters. If $\angle PQC=45^{0}$ , and the ratio of the perpendicular distance of $PQ$ and $SR$ from $C$ is $3:2$ , then the area, in sq. cm, of the quadrilateral $PQRS$ is

In a circle with center C and radius $6\sqrt{2}$ cm, PQ and SR are two parallel chords separated by one of the diameters. If $\angle PQC=45^{0}$ , and the ratio of the perpendicular distance of $PQ$ and $SR$ from $C$ is $3:2$ , then the area, in sq. cm, of the quadrilateral $PQRS$ is