Let f(x) = min ($${2x^{2},52-5x}$$) where x is any positive real number. Then the maximum possible value of f(

Question

Let f(x) = min ($${2x^{2},52-5x}$$) where x is any positive real number. Then the maximum possible value of f(x) is

Accepted Answer

f(x) = min ( 2 x 2 , 52 − 5 x {2x^{2},52-5x} 2 x 2 , 52 − 5 x ) The maximum possible value of this function will be attained at the point in which 2 x 2 2x^2 2 x 2 is equal to 52 − 5 x 52-5x 52 − 5 x . 2 x 2 = 52 − 5 x 2x^2 = 52-5x 2 x 2 = 52 − 5 x 2 x 2 + 5 x − 52 = 0 2x^2+5x-52=0 2 x 2 + 5 x − 52

Let f(x) = min (2x2,52−5x{2x^{2},52-5x}2x2,52−5x) where x is any positive real number. Then the maximum possible value of f(x) is

Let f(x) = min ( ${2x^{2},52-5x}$ ) where x is any positive real number. Then the maximum possible value of f(x) is