Let f(x)=x2+ax+bf(x)=x^{2}+ax+bf(x)=x2+ax+b and g(x)=f(x+1)−f(x−1)g(x)=f(x+1)-f(x-1)g(x)=f(x+1)−f(x−1). If f(x)≥0f(x)\geq0f(x)≥0 for all real x, and g(20)=72g(20)=72g(20)=72. then the smallest possible value of b is
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