Let x and y be positive real numbers such thatlog5(x+y)+log5(x−y)=3,\log_{5}{(x + y)} + \log_{5}{(x - y)} = 3,log5(x+y)+log5(x−y)=3, and log2y−log2x=1−log23\log_{2}{y} - \log_{2}{x} = 1 - \log_{2}{3}log2y−log2x=1−log23. Then xyxyxy equals
150
25
100
250
Select an option to reveal the answer and explanation
Practice the full paper
Attempt CAT 2019 Question Paper Slot 1 with real exam interface and instant grading.