Suppose k is any integer such that the equation $$2x^{2}+kx+5=0$$ has no real roots and the equation $$x^{2}+(

Question

Suppose k is any integer such that the equation $$2x^{2}+kx+5=0$$ has no real roots and the equation $$x^{2}+(k-5)x+1=0$$ has two distinct real roots for x. Then, the number of possible values of k is

Accepted Answer

9. 2 x 2 + k x + 5 = 0 2x^{2}+kx+5=0 2 x 2 + k x + 5 = 0 has no real roots so D<0 k^2-40\ &lt;0 \left(k-\sqrt{40}\right)\left(k+\sqrt{40}\right)&lt;0 k ∈ ( − 40 , 40 ) k\in\left(-\sqrt{40},\sqrt{40}\right) k ∈ ( − 40 ​ , 40 ​ ) x 2 + ( k − 5 ) x + 1 = 0 x^{2}+(k-5)x+1=0 x 2 + ( k − 5 ) x + 1

Suppose k is any integer such that the equation $2x^{2}+kx+5=0$ has no real roots and the equation $x^{2}+(k-5)x+1=0$ has two distinct real roots for x. Then, the number of possible values of k is

Suppose k is any integer such that the equation $2x^{2}+kx+5=0$ has no real roots and the equation $x^{2}+(k-5)x+1=0$ has two distinct real roots for x. Then, the number of possible values of k is

Suppose k is any integer such that the equation 2x2+kx+5=02x^{2}+kx+5=02x2+kx+5=0 has no real roots and the equation x2+(k−5)x+1=0x^{2}+(k-5)x+1=0x2+(k−5)x+1=0 has two distinct real roots for x. Then, the number of possible values of k is

Suppose k is any integer such that the equation 2x2+kx+5=02x^{2}+kx+5=02x2+kx+5=0 has no real roots and the equation x2+(k−5)x+1=0x^{2}+(k-5)x+1=0x2+(k−5)x+1=0 has two distinct real roots for x. Then, the number of possible values of k is

Suppose k is any integer such that the equation $2x^{2}+kx+5=0$ has no real roots and the equation $x^{2}+(k-5)x+1=0$ has two distinct real roots for x. Then, the number of possible values of k is

Suppose k is any integer such that the equation $2x^{2}+kx+5=0$ has no real roots and the equation $x^{2}+(k-5)x+1=0$ has two distinct real roots for x. Then, the number of possible values of k is