The minimum possible value of $$\frac{x^{2} - 6x + 10}{3-x}$$, for $$x

Question

The minimum possible value of $$\frac{x^{2} - 6x + 10}{3-x}$$, for $$x < 3$$, is

Accepted Answer

2. Let x 2 − 6 x + 10 3 − x = p \frac{x^2-6x+10}{3-x}=p 3 − x x 2 − 6 x + 10 ​ = p x 2 − 6 x + 10 = 3 p − p x x^2-6x+10=3p-px x 2 − 6 x + 10 = 3 p − p x x 2 − ( 6 − p ) x + 10 − 3 p = 0 x^2-\left(6-p\right)x+10-3p=0 x 2 − ( 6 − p ) x + 10 − 3 p = 0 Since the equation will have real roots, ( 6 − p ) 2 −

The minimum possible value of $\frac{x^{2} - 6x + 10}{3-x}$ , for $x < 3$ , is

The minimum possible value of $\frac{x^{2} - 6x + 10}{3-x}$ , for $x < 3$ , is

The minimum possible value of x2−6x+103−x\frac{x^{2} - 6x + 10}{3-x}3−xx2−6x+10​, for x &lt; 3, is

The minimum possible value of x2−6x+103−x\frac{x^{2} - 6x + 10}{3-x}3−xx2−6x+10​, for x &lt; 3, is

The minimum possible value of $\frac{x^{2} - 6x + 10}{3-x}$ , for $x < 3$ , is

The minimum possible value of $\frac{x^{2} - 6x + 10}{3-x}$ , for $x < 3$ , is