The number of integer solutions of equation $$2|x|(x^{2}+1) = 5x^{2}$$ is

Question

Accepted Answer

Let us consider 3 cases: 1) x = 0, This is a solution, as both L.H.S and R.H.S will be equal (0) when x = 0. (1 solution) 2) x > 0 => 2 x ( x 2 + 1 ) = 5 x 2 2x\left(x^2+1\right)=5x^2 2 x ( x 2 + 1 ) = 5 x 2 => 2 ( x 2 + 1 ) = 5 x 2\left(x^2+1\right)=5x 2 ( x 2 + 1 ) = 5 x => 2 x 2 − 5 x

The number of integer solutions of equation $2|x|(x^{2}+1) = 5x^{2}$ is

The number of integer solutions of equation $2|x|(x^{2}+1) = 5x^{2}$ is

The number of integer solutions of equation 2∣x∣(x2+1)=5x22|x|(x^{2}+1) = 5x^{2}2∣x∣(x2+1)=5x2 is

The number of integer solutions of equation 2∣x∣(x2+1)=5x22|x|(x^{2}+1) = 5x^{2}2∣x∣(x2+1)=5x2 is

The number of integer solutions of equation $2|x|(x^{2}+1) = 5x^{2}$ is

The number of integer solutions of equation $2|x|(x^{2}+1) = 5x^{2}$ is