The number of solutions to the equation $$\mid x \mid (6x^2 + 1) = 5x^2$$ is

Question

Accepted Answer

For x <0, -x( 6 x 2 + 1 6x^2+1 6 x 2 + 1 ) = 5 x 2 5x^2 5 x 2 => ( 6 x 2 + 1 6x^2+1 6 x 2 + 1 ) = -5x => ( 6 x 2 + 5 x + 1 6x^2 + 5x+ 1 6 x 2 + 5 x + 1 ) = 0 =>( 6 x 2 + 3 x + 2 x + 1 6x^2 + 3x+2x+ 1 6 x 2 + 3 x + 2 x + 1 ) = 0 => (3x+1)(2x+1)=0 =>x= − 1 3 \ -\frac{\ 1}{3} − 3 1 ​

The number of solutions to the equation $\mid x \mid (6x^2 + 1) = 5x^2$ is

The number of solutions to the equation $\mid x \mid (6x^2 + 1) = 5x^2$ is

The number of solutions to the equation ∣x∣(6x2+1)=5x2\mid x \mid (6x^2 + 1) = 5x^2∣x∣(6x2+1)=5x2 is

The number of solutions to the equation ∣x∣(6x2+1)=5x2\mid x \mid (6x^2 + 1) = 5x^2∣x∣(6x2+1)=5x2 is

The number of solutions to the equation $\mid x \mid (6x^2 + 1) = 5x^2$ is

The number of solutions to the equation $\mid x \mid (6x^2 + 1) = 5x^2$ is