The probability that a randomly chosen positive divisor of $10^{… | XAT 2014 Question Paper

XAT 2014Quantitative AbilityProbability, CombinatoricsMEDIUM+1 / −0.25

The probability that a randomly chosen positive divisor of $10^{29}$ is an integer multiple of $10^{23}$ is: $a^{2} /b^{2}$ , then ‘b - a’ would be:

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XAT 2014Quantitative AbilityProbability, CombinatoricsMEDIUM+1 / −0.25

The probability that a randomly chosen positive divisor of $10^{29}$ is an integer multiple of $10^{23}$ is: $a^{2} /b^{2}$ , then ‘b - a’ would be:

Select an option to reveal the answer and explanation

Practice the full paper

Attempt XAT 2014 Question Paper with real exam interface and instant grading.