Three positive integers x, y and z are in arithmetic progression. If $y-x>2$ and $xyz=5(x+y+z)$ , then z-x equals
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Question

Three positive integers x, y and z are in arithmetic progression. If $$y-x>2$$ and $$xyz=5(x+y+z)$$, then z-x equals

Accepted Answer

14. Given x, y, z are three terms in an arithmetic progression. Considering x = a, y = a+d, z = a+2*d. Using the given equation x*y*z = 5*(x+y+z) a*(a+d)*(a+2*d) = 5*(a+a+d+a+2*d) =a*(a+d)*(a+2*d) = 5*(3*a+3*d) = 15*(a+d). = a*(a+2*d) = 15. Since all x, y, z are positive integers and y-x > 2. a, a+d,

Three positive integers x, y and z are in arithmetic progression. If y-x&gt;2 and xyz=5(x+y+z)xyz=5(x+y+z)xyz=5(x+y+z), then z-x equals

Three positive integers x, y and z are in arithmetic progression. If y-x&gt;2 and xyz=5(x+y+z)xyz=5(x+y+z)xyz=5(x+y+z), then z-x equals

Three positive integers x, y and z are in arithmetic progression. If $y-x>2$ and $xyz=5(x+y+z)$ , then z-x equals

Three positive integers x, y and z are in arithmetic progression. If $y-x>2$ and $xyz=5(x+y+z)$ , then z-x equals