Train T leaves station X for station Y at 3 pm. Train S, traveling at three quarters of the speed of T, leaves

Question

Train T leaves station X for station Y at 3 pm. Train S, traveling at three quarters of the speed of T, leaves Y for X at 4 pm. The two trains pass each other at a station Z, where the distance between X and Z is three-fifths of that between X and Y. How many hours does train T take for its journey from X to Y?

Accepted Answer

Train T starts at 3 PM and train S starts at 4 PM. Let the speed of train T be t. => Speed of train S = 0.75t. When the trains meet, train t would have traveled for one more hour than train S. Let us assume that the 2 trains meet x hours after 3 PM. Trains S would have traveled for x-1 hours. Dis