Two cars travel the same distance starting at 10:00 am and 11:00 am, respectively, on the same day. They reach

Question

Two cars travel the same distance starting at 10:00 am and 11:00 am, respectively, on the same day. They reach their common destination at the same point of time. If the first car travelled for at least 6 hours, then the highest possible value of the percentage by which the speed of the second car could exceed that of the first car is

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Accepted Answer

20. Let the speed of cars be a and b and the distance =d Minimum time taken by 1st car = 6 hours, For maximum difference in time taken by both of them, car 1 has to start at 10:00 AM and car 2 has to start at 11:00 AM. Hence, car 2 will take 5 hours. Hence a= d 6 \ \frac{\ d}{6} 6 d ​ and b = d 5 \ \fra