Two tangents drawn from a point P and a circle with center O at point Q and R. Point A and B lie on PQ and PR,

Question

Two tangents drawn from a point P and a circle with center O at point Q and R. Point A and B lie on PQ and PR, repectively, such that AB is also a tangent to the same circle. If $$\angle AOB=50^{0}$$, then $$\angle APB$$, in degrees equals

Accepted Answer

We can draw the following diagram as per the given question : Now, taking △ A O T 	riangle AOT △ A O T and △ A O Q 	riangle AOQ △ A O Q AO is the common side AT=AQ (Tangents drawn from an external point are equal in length) OT=OQ (radius of circle) So, by S.S.S., △ A O T 	riangle\ AOT △ A O T is

Two tangents drawn from a point P and a circle with center O at point Q and R. Point A and B lie on PQ and PR, repectively, such that AB is also a tangent to the same circle. If $\angle AOB=50^{0}$ , then $\angle APB$ , in degrees equals

Two tangents drawn from a point P and a circle with center O at point Q and R. Point A and B lie on PQ and PR, repectively, such that AB is also a tangent to the same circle. If $\angle AOB=50^{0}$ , then $\angle APB$ , in degrees equals

Two tangents drawn from a point P and a circle with center O at point Q and R. Point A and B lie on PQ and PR, repectively, such that AB is also a tangent to the same circle. If ∠AOB=500\angle AOB=50^{0}∠AOB=500, then ∠APB\angle APB∠APB, in degrees equals

Two tangents drawn from a point P and a circle with center O at point Q and R. Point A and B lie on PQ and PR, repectively, such that AB is also a tangent to the same circle. If ∠AOB=500\angle AOB=50^{0}∠AOB=500, then ∠APB\angle APB∠APB, in degrees equals

Two tangents drawn from a point P and a circle with center O at point Q and R. Point A and B lie on PQ and PR, repectively, such that AB is also a tangent to the same circle. If $\angle AOB=50^{0}$ , then $\angle APB$ , in degrees equals

Two tangents drawn from a point P and a circle with center O at point Q and R. Point A and B lie on PQ and PR, repectively, such that AB is also a tangent to the same circle. If $\angle AOB=50^{0}$ , then $\angle APB$ , in degrees equals